Jul 8, 2015

iology Module 1 - 1.aspects of biochemistry 1.10 carry out tests for reducing and non reducing sugar, strach lipids and proteins

1.10 carry out tests for reducing and non reducing sugar, starch lipids and proteins



Test for reducing sugar


add an equal volume of benedict's solution to equal volume of test solution. Then boil in water bath and observe colour changes.




Positive - colour changes from blue to green/yellow/orange/ red. This is because sugar reduces copper (II) ions to copper (I) ions


Negative - no change; remains blue



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Test for non - reducing sugar


Test solution for reducing sugar before testing for non-reducing sugar


Add a few drop of hydrocholoric acid (HCl) and boil for a few mintues. Then add dilute sodium hydroxide or sodium hydrogen carbonate. When neutralised add benedicts solution then boil in water bath and observe colour changes



Positive - colour changes from blue to green/yellow/orange/red. This is because HCl hydrolyses sucrose to fructose and glucose that are both reducing sugars


Negative - no change; remains blue



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Test for starch


using a pipette, add iodine solution to solution in test tube or to solid substance on white tile



Positive - colour changes from yellow-orange to blue-black. This is because iodine binds to center of helix of amylose to form starch iodine complex which is a blue-black colour 



Negative - no colour change



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Test of Lipid


add crushed solid substance or liquid in a test tube and add ethanol to dissolve. Then pour off ethanol which dissolved some lipids into a test tube of water and do not mix.     



Positive - white cloudiness (emulsion). This is because ethanol dissolves lipids and when the water is added the lipid is dispersed throughout the water as tiny particles which is an emulsion



Negative - no change


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Test for protein


add solution with test tube. then add the same volume of biuret solution( solution of copper sulphate and sodium hydroxide) and mix 



Positive - colour changes from blue to purple/lilac. This is because a coloured complex forms where there are peptide bonds



Negative - no change